Question

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a car of mass 100kg travelling 32m/sec dashes into the rear of a truck of mass 8000kg moving in the same direction with a velocity of 4m/sec .after the collision ,the car bounces with a velocity of 80m/sec . what is the velocity of truck after the impact.

Answer 1

Mass of car, m = 1000 kg

Speed of car, u = 32 m/s

Mass of truck, M = 8000 kg

Speed of truck, U = 4 m/s

Before collision,

Total momentum = momentum of car + momentum of truck is

= (1000)(32) + (8000)(4)

= 32000 + 32000

= 64000 Ns

After collision, the velocity of the car is, v = -8 m/s. Let the velocity of the truck be V.

So, total momentum after collision = (1000)(-8) + (8000)V = 8000(V – 1)

By law of conservation of momentum,

Total momentum after collision = total momentum before collision
=> 8000(V-1) = 64000

=> V – 1 = 8

=> V = 9 m/s

This is the velocity of the truck after collision.

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Answer 2

M1u1+M2u2=m1v1+m2v2
8000*4+100*32=-100*80+8000*v2
32000+3200=-8000+8000v2
40000+3200=8000v2
V2=5+0.4=5.4