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Total energy of the particle, E = 1 J Force constant, k = 0.5 N m–1 Kinetic energy of the particle, K = (1/2)mv2 According to the conservation law: E = V + K 1 = (1/2)kx2 + (1/2)mv2 At the moment of ‘turn back’, velocity (and hence K) becomes zero. 1 = 1/2 kx2 Hence, the particle turns back when it reaches x = ± 2 m.
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