Question

answer plz
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Answer 1

Answer:

Given :-

Initial speed ( u ) = 90 km/hr = 90 * 5/18 = 25 m/s

final speed ( v ) = 0 m/s

acceleration ( a ) = 2 m/s

distance ( s ) = ?

We know that ,

2as = v^2 - u^2

2 ( -2 ) s = 0 - 625

- 4s = - 625

s = 625/4 = 156.25 m

Hence the train will stop after 156.25 m after application of brakes .