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Explanation:
- Mass of bullet (m) = 10g = 0.01 Kg
- Initial speed of bullet (u1) = 400 m/s
- Mass of block (M) = 900g = 0.9 Kg
- Initial speed of block (u2) = 0
After collision bullet get struck in the block, so they will have common velocity Vcom
By conservation of Linear Momentum
Initial Momentum = Final Momentum
- M1U1 + M2U2 = M1V1 + M2V2
- m u1 + M u2 = (M1+M2) Vcom
- 0.01 × 400 + 0.9 × 0 = (0.9 + 0.01) Vcom
- 4 = 0.91 Vcom
- Vcom = 4 / 0.91
- Vcom = 4.40 m/s
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