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A square hole of side length l is made at a depth of h and a circular hole is made at a depht of 4 h from the surface of water in a water tank kept on a horizontal surface (where l ltlt h). Find the radius r of the circular hole if equal amount of water comes out of the vessel through the holes per second.
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Answer:
r = a÷√2π
Explanation:
a square whole of side a made at a depth h below water surface and to the side of water container another circular hole of radius r is made to the same container at a depth of 4 h .it is found that volume flows rate of water throughboth the hole is found to be same then:
r = a ÷ √ 2π
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