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✨hey mate!✨
(2) (a) since, 0°C = 32°F
so, 30°C = 30*9/5+32
= 86°F
and, 80°F = (80°F-32)×5/9
= 26.666666667°C
(b) the value of normal body temperature with a laboratory thermometer is 37°C.
hope it is helpful!✌️
(2) (a) since, 0°C = 32°F
so, 30°C = 30*9/5+32
= 86°F
and, 80°F = (80°F-32)×5/9
= 26.666666667°C
(b) the value of normal body temperature with a laboratory thermometer is 37°C.
hope it is helpful!✌️
WritersParadise01:
thnx for the mark!
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