Question

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Answer 1

12) :-

1) We know that OB = OC which is the radius

The base angles of an isosceles triangle are equal

So we get

∠OBC = ∠OCB = 55°

In △ BOC

Using the angle sum property

∠BOC + ∠OCB + ∠OBC = 180°

By substituting the values

∠BOC + 55° + 55° = 180°

On further calculation

∠BOC = 180° – 55° – 55°

By subtraction

∠BOC = 180° – 110°

So we get ∠BOC = 70°

(ii) We know that OA = OB which is the radius

The base angles of an isosceles triangle are equal

So we get

∠OBA= ∠OAB = 20°

In △ AOB

Using the angle sum property

∠AOB + ∠OAB + ∠OBA = 180°

By substituting the values ∠AOB + 20° + 20° = 180° On further calculation ∠AOB = 180°– 20°– 20°By subtraction ∠AOB = 180°– 40° So we get ∠AOB = 140°We know that ∠AOC = ∠AOB – ∠BOC

By substituting the values

∠AOC = 140°– 70°

So we get ∠AOC = 70°

Answer 2

Answer:

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