Answer plz...-Find the remainder when 2x power 4+ ax cube - 3a square X square + 6x is divided by x- a ???
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X-a ) 2x^4 +ax^3 -3a^2x^2+6x ( 2x^3+3ax^2+6
2x ^4 - 2ax^3
———————-
3ax^3 -3a^2x^2
3ax^3 - 3a^2x^2
———————————
0. + 0. +6x + 0
6x -6a
————————————————————
Remainder is 6a
2x ^4 - 2ax^3
———————-
3ax^3 -3a^2x^2
3ax^3 - 3a^2x^2
———————————
0. + 0. +6x + 0
6x -6a
————————————————————
Remainder is 6a
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