answer plz its urgent
2.3g of ethanol is added to 500g of water determine the molality of the resulting solution.
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Molality = moles of solute / mass of solvent (in kg)
moles of ethanol = mass / molecular weight
=> moles of ethanol = 2.3 /46 = 0.05
mass of solvent = 0.5 kg (given)
So, molality = 0.05/0.5 = 0.1 moles/kg ....
moles of ethanol = mass / molecular weight
=> moles of ethanol = 2.3 /46 = 0.05
mass of solvent = 0.5 kg (given)
So, molality = 0.05/0.5 = 0.1 moles/kg ....
Answered by
2
1) Determine the molality of the menthol solution:
(2.3 g / 156.267 g/mol) / 0.0590 kg = 3.17796 m
2) We utilize this formula:
Δt = i Kb m
x = (1) (3.85 °C kg mol-1) (3.17796 mol/kg)
x = 12.2 °C
61.2 + 12.2 = 73.4 °C <--- this is the bp of the solution
(2.3 g / 156.267 g/mol) / 0.0590 kg = 3.17796 m
2) We utilize this formula:
Δt = i Kb m
x = (1) (3.85 °C kg mol-1) (3.17796 mol/kg)
x = 12.2 °C
61.2 + 12.2 = 73.4 °C <--- this is the bp of the solution
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