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when released from height a ball falls 5m in 1 sec .in 4 sec after release it will fall....
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Answered by
4
Here is your answer....
My attempt: Since the body is released from a certain height, u=0
Therefore, H=(0.5)gt^2
In 4 seconds, displacement of the particle from the point of release = (0.5)g (4)^2 = 80 m.
Answer :- 80m
Hope it helps you.
My attempt: Since the body is released from a certain height, u=0
Therefore, H=(0.5)gt^2
In 4 seconds, displacement of the particle from the point of release = (0.5)g (4)^2 = 80 m.
Answer :- 80m
Hope it helps you.
where
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I updated my answer.
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Answered by
3
S =ut+1/2gt^2
5=1/2g*1*1=1/2*g
g =10
S =1/2 *g *4*4=8g=8*10=80m
5=1/2g*1*1=1/2*g
g =10
S =1/2 *g *4*4=8g=8*10=80m
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