Question

answer plz with diagram

Class 9th☺️☺️❤️​

Answer 1

Answer:

Solution :

Let AB be a chord of a circle with centre O and radius 17 cm.

Draw OL ⊥ AB. Join OA.

Then , OL=8cm and OA=17cm.

From the right ΔOLA , we have

OA^2=OL^2+AL^2

⇒AL^2=OA^2−OL^2=[(17)^2−(8)^2]cm^2

=(17+8)(17−8)cm^2=225cm^2

⇒AL=√225=15cm.

Since the perpendicular fromthe centre of a circle to a chord bisects the chord, we have

AB=2×AL=(2×15)cm=30cm

Answer 2

Answer:

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Step-by-step explanation:

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