Question

answer plzz
$\frac{2}{9} of \: 2 \times \frac{1}{3} \times 3 \times \frac{1}{3} \div ( \frac{1}{9} + \frac{2}{3} )$
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Answer 1

Answer:

20/9

Step-by-step explanation:

$= \frac{2}{9} \times \frac{7}{3} \times \frac{10}{3} \div ( \frac{1}{9} + \frac{2}{3} ) \\ = \frac{140}{81} \div ( \frac{1 + 6}{9} ) \\ = \frac{140}{81} \div \frac{7}{9} \\ = \frac{140}{81} \times \frac{9}{7} \\ = \frac{20}{9}$

hope you get your answer