Question

answer plzzz 1+3+5+7+9..............................................................................................................................103+105 is the square of which number dare not to give blank or irrelevant answers and the best answer would get 100 points+brainliest+will be thanked+.....

Answer 1

Answer:

$\implies$

Step-by-step explanation:

The above series forms an Arithemetic Progression (A.P).

• An arithmetic progression is a sequence of numbers such that the difference of any two successive members is a constant.

For example,

• the sequence 1, 2, 3, 4, ... is an arithmetic progression with common difference 1.
• Second example: the sequence 3, 5, 7, 9, 11,... is an arithmetic progression with common difference 2.

Now the above series

• 1+3+5+………+97+99

We can solve this in two ways

Solution:

Using Progression Concept

The Common Difference is 3–1 = 2

Total no of terms can be found using below formula

T1 = a+(n-1)d

Tn is the nth Term

a is the First Ter

n is the no of Terms

d is the common difference

Here Tn is , d=2

99 = 1+(n-1)2;

98= 2n-2;

2n = 100;

n = 50;

There are total 50 terms in this series. Sun can be found using below formula

Sum

S=n/2a+l

Where n is the no of terms

a is the first term and l is the last term

• S = 50/2{1+99}
• S = 25*100;
• S = 250

hope it helps uh!!

Answer 2

Answer:

i dont know

Step-by-step explanation: