Math, asked by labanskumar, 11 months ago

Answer plzzz❤️❤️
will mark as BRAINLIST ✌️✌️​

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Answered by tanushree8320
1

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hope it helps........

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Answered by shadowsabers03
1

Let the boy be at a distance d fron the temple initially. Then,

30-1.5=d\tan30^{\circ}\\\\\\d=28.5\sqrt{3}

After moving x distance towards the temple,

d-x=\dfrac {28.5}{\tan60^{\circ}}\\\\\\28.5\sqrt{3}-x=\dfrac {28.5}{\sqrt3}\\\\\\x=28.5\left (\sqrt3-\dfrac {1}{\sqrt3}\right)\\\\\\\underline {\underline {x=32.9\ m}}

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