Question

answer plzzzz fast...............

Answer 1

let the sides be a and b
therefore the perimeters are 4a and 4b
the total area = a^2+b^2=15425
by given data , 4a-4b= 60
a-b=60/4 =>. a-b=15
a=15-b
sub a= 15-b in the first en
(15-b)^2 +b^2=15425
225+b^2-30b+b^2=15425
2b^2-30b=15425-225
2b^2-30b=15200
b^2-15b=7600
b^2-15b-7600
(b+80)(b-95)=0
therefore b=95 or -80
therefore a= -80 or 95
therefore the sides are 95m and 80m
if 95m is considered to be a
then he is more concentrated on providing free education