Physics, asked by Anonymous, 1 year ago

answer plzzzzz if earth is four times its present distance from Sun , the duration of the year will be

ayan7456: According to Kepler's third law, the square of orbital period, T, of a planet is proportional to the cube of its mean distance, R, from the sun.

T2 ∝ R3

T ∝ √R3
T1/T2 = √R13 / √R23
         = √R13 / (√(R1/4)3
         = √(43)
         = 8

T2 = T1/8 .....So , the answer is one - eighth year or 1/8 year ^_^

ayan7456: it's looking like a mess ,sorry i just mistakenly close ed the app when i was anserwing

Dhinu: but.. she said ... distance is 4 times ... not 1/4 times...

Dhinu: you put R/4 .... it should be 4R there ....

Dhinu: in your solution... @ayan7456

ayan7456: oh

Dhinu: ya!

Answers

Answered by Dhinu

the solution is a bit long so... I posted 2 pics...
Ans.:- the duration of the year will be 8 times of the present duration......
btw, the main concept of it is... the square of time period of a planet is directly proportional to the cube of the distance between the planet and sun....
hope you'll get my solution.. and if not.. then comment , I'll edit it and try to make it better ...

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Answered by billu004

hope it helps u......

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