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I think The second option has maximum energy due to n+l rule .
If you think that option b and c and d's n+l values are same . Then option c is not even possible , because of hund's law.
and because 2nd option has more electrons then option d , 2nd one has more energy .
If you think that option b and c and d's n+l values are same . Then option c is not even possible , because of hund's law.
and because 2nd option has more electrons then option d , 2nd one has more energy .
jitesh2019:
last three options
no B option is according to hund's rule. Check again hund's rule 's definition carefully
i think acc. to hunds rule pairing should take place in 3p orbitals before they enter into the 3d orbitals
oh it's their excited state , it doesn't offend hund's rule fruend
friend
okay, thnx for the explanation
can u explain other two questions
mark as brainliest plz , yes i will answer them
am waiting for ur answer
hey
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