answer plzzzzzzzz this question is very interesting
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Step-by-step explanation:
AC = 24cm
BC = 10cm
By Pythagoras,
√24² + 10² = AB
√676=AB
AB=26
THEREFORE DIAMETER = 26CM
RADIUS = 13 CM
AREA OF A CIRCLE = πr²
= π 13²
= 169 x 3.14
=530.66
area of circle = 530.66 cm²
area of semicircle = 530.66/2
= 265.33cm²
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PLS MARK IT AS BRAINLIEST
PLS MARK IT AS BRAINLIEST PLS
Answered by
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heya!!!
Required are = π ( OA )² / 2 - 1 /2 ( 10×24)
OA = OB
OA + OB = AC
AC² = AB² + BC²
AC² = 676
AC = 26
OA = 13cm
required area = 3.14 × 13² /2 - 120
265.33 - 120 = 145.33cm²
Required are = π ( OA )² / 2 - 1 /2 ( 10×24)
OA = OB
OA + OB = AC
AC² = AB² + BC²
AC² = 676
AC = 26
OA = 13cm
required area = 3.14 × 13² /2 - 120
265.33 - 120 = 145.33cm²
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