answer plzzzzzzzzzzz
Attachments:
Answers
Answered by
1
Given:
P = b-x^2/at
x=distance=[L]
dimensions of b will be equivalent to dimensions of [x^2]
dimensions of b = [L2]
P.at = b-x^2
As the dimensions of Power is [ML2T-3]
Put in the condition
[ML2T-3] [a][T] = [L2]
[a] = [M-1 T2] .
P = b-x^2/at
x=distance=[L]
dimensions of b will be equivalent to dimensions of [x^2]
dimensions of b = [L2]
P.at = b-x^2
As the dimensions of Power is [ML2T-3]
Put in the condition
[ML2T-3] [a][T] = [L2]
[a] = [M-1 T2] .
billu004:
khush
phir comments delete kar wane ha kya
Similar questions