Question

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Answer 1

Given:

P = b-x^2/at 

x=distance=[L] 

dimensions of b will be equivalent to dimensions of [x^2] 

dimensions of b = [L2] 

P.at = b-x^2 

As the dimensions of Power is [ML2T-3] 

Put in the condition 

[ML2T-3] [a][T] = [L2] 

[a] = [M-1 T2] .