Question

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Answer 1

mode=l+(f1-f0)/(2f1-f0-f2) xh

l=35

f=230

fo=210

f2=150

h=10

mode= 35+(230-210) /(460-210-150) x10

mode=35+(20) /100) x10

mode=350+20/10

mode=370/10

mode=37

hence the mode of the given data is 37

Answer 2

35-45 is the modal class, since it has the highest frequency.

Hope it will help you.