Answer Q15 and Q14
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here's your answer of que 15
16)
d= 14m
volume of hemispherical tank = 2/3 pie r^3
= 2/3*22/7*14*14*14
= 5749.3 m^3
now,
1m^3 = 1kl
therefore 5749.3m^3= 5749.3kl
now to calculate the remaining vol. of water to be filled = 5749.3- 40 kl
= 5709.3 kl
16)
d= 14m
volume of hemispherical tank = 2/3 pie r^3
= 2/3*22/7*14*14*14
= 5749.3 m^3
now,
1m^3 = 1kl
therefore 5749.3m^3= 5749.3kl
now to calculate the remaining vol. of water to be filled = 5749.3- 40 kl
= 5709.3 kl
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