answer Q17.......plzzzzz
Attachments:
Answers
Answered by
1
√y x⁻¹ . √z y⁻¹ .√x z⁻¹
=(√y .1/x)(√z.1/y)(√√x.1/z)
=(√y/x)(√z/y)(√x/z)
=(√y/√x)×(√z/√y)×(√x/√z)
=1
∴√y x⁻¹ . √z y⁻¹ .√x z⁻¹=1
=(√y .1/x)(√z.1/y)(√√x.1/z)
=(√y/x)(√z/y)(√x/z)
=(√y/√x)×(√z/√y)×(√x/√z)
=1
∴√y x⁻¹ . √z y⁻¹ .√x z⁻¹=1
Answered by
2
here is the answer..
plzz mark it as a brainliest answer
plzz mark it as a brainliest answer
Attachments:
Similar questions