Math, asked by sharmalalit008, 10 months ago

Answer Q6,7,8,9 with explanation

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Answered by mitajoshi11051976
0

 = ( {4 }^{2}  -  {2}^{2} )  \times  ({\frac{2}{3} )}^{ - 2}  \\  = (16 - 4) \times ({\frac{2}{3} )}^{ - 2} \:  \\  = 12 \times ({\frac{2}{3} )}^{ - 2} \:  \\  = 12 \times  \frac{ {2}^{ - 2} }{ {3 }^{ - 2} }  \\  =  {2}^{2}  \times 3 \times  {2}^{ - 2}   \times {3 }^{2}  \\  =  {2}^{2 - 2}  \times  {3}^{2 + 1}  \\  =  {3}^{3}  \\  = 27

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