Answer Q6 any part! Please...
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Given
= > 35x + 23y = 209 ------ (1)
= > 23x + 35y = 197. ------ (2)
On Adding (1) & (2), we get
58x + 58y = 406
x + y = 7 ------- (3)
On Subtracting (1) & (2), we get
12x - 12y = 12
x - y = 1 ------- (4)
On solving (3) & (4), we get
x + y = 7
x - y = 1
------------------
2x = 8
x = 4.
Substitute x = 4 in (3), we get
x + y = 7
4 + y = 7
y = 3.
Therefore the value of x = 4 and y = 3.
Hope this helps!
= > 35x + 23y = 209 ------ (1)
= > 23x + 35y = 197. ------ (2)
On Adding (1) & (2), we get
58x + 58y = 406
x + y = 7 ------- (3)
On Subtracting (1) & (2), we get
12x - 12y = 12
x - y = 1 ------- (4)
On solving (3) & (4), we get
x + y = 7
x - y = 1
------------------
2x = 8
x = 4.
Substitute x = 4 in (3), we get
x + y = 7
4 + y = 7
y = 3.
Therefore the value of x = 4 and y = 3.
Hope this helps!
:-)
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