Math, asked by goopy81baby, 1 year ago

answer question 14 please

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Answered by Anonymous
1
given quadratic is y=ax^2 +bx
which is passing through
(0,0)
(4,0)
(8,96)
so y = 0 when X= 0 and 4
put X = 4 in quadratic
16a+4b = 0
b = -4a------1
since y= 96
when X = 8
put X = 8 in quadratic
64a+8b = 96
from eqn 1
64a+8(-4a) = 96
32a= 96
a=3
put a= 3 in eqn ----1
so b = -12
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