Question

Answer question 15 plssssss .

Answer 1

Here, TS || QR and TV || QS

In ΔPQR,

$\frac{PT}{TQ} = \frac{PS}{SR}$

In ΔPQS,

$\frac{PT}{TQ} = \frac{PV}{VS}$

Comparing bith triangles,

$\frac{PV}{VS} = \frac{PS}{SR}$