Question

Answer question 4 pleasr

Answer 1

$\textbf{ \large{ \underline{ Hello Mate! }}}$

Area of trapezium = $\frac{1}{2}$ × h ( sum of parallel sides )

$28 cm^2 = \frac{1}{2} \times h( 8 m + 60 dm )$

Here, 60 dm = 60 / 10 m = 6 m [ 1 m = 10 dm ]

28 m^2 = 1 / 2 × h ( 8 + 6 ) m

28 m^2 = 1 / 2 × 14h

28 m^2 × 2 × 1 /14m = h

4 m = height.

$\boxed{ Altitude\:is\:4\:m }$

Have great future ahead!

Answer 2

Hello!

• a = $\bf{8\: m}$
• b = 60 dm = $\bf{6 \:m}$

Then,

$\bf{Area} = 28\:m^{2} \\ \\ \implies \dfrac{1}{2}(\sf Sum\: of \:parallel\: sides) \times \sf h = 28 \\ \\ \implies \dfrac{\sf a + b}{2} \sf h = 28 \\ \\ \implies \dfrac{8+6}{2} \times \sf h = 28 \\ \\ \implies \dfrac{14}{2} \times \sf h = 28 \\ \\ \implies 7 \times \sf h = 28 \\ \\ \implies \sf h = \dfrac{28}{7} \implies \boxed{\red{\bf{h = 4\:cm}}}$

Cheers!