Question

Answer Question 5 Class 7 NCERT Question Exercise 11.4

Answer 1

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answer Let ABCD, the square garden of side= 30 m.

answer Let ABCD, the square garden of side= 30 m.PQRS is the region inside the garden.

answer Let ABCD, the square garden of side= 30 m.PQRS is the region inside the garden.so,

answer Let ABCD, the square garden of side= 30 m.PQRS is the region inside the garden.so,PQ = (30 -1-1 ) = 28 m

answer Let ABCD, the square garden of side= 30 m.PQRS is the region inside the garden.so,PQ = (30 -1-1 ) = 28 malso

answer Let ABCD, the square garden of side= 30 m.PQRS is the region inside the garden.so,PQ = (30 -1-1 ) = 28 malsoPS = ( 30 – 1 – 1 ) = 28 m

answer Let ABCD, the square garden of side= 30 m.PQRS is the region inside the garden.so,PQ = (30 -1-1 ) = 28 malsoPS = ( 30 – 1 – 1 ) = 28 m (i) Area of the path = Area of ABCD – Area of PQRS

answer Let ABCD, the square garden of side= 30 m.PQRS is the region inside the garden.so,PQ = (30 -1-1 ) = 28 malsoPS = ( 30 – 1 – 1 ) = 28 m (i) Area of the path = Area of ABCD – Area of PQRS = [( 30 x 30) – (28 x 28)]

answer Let ABCD, the square garden of side= 30 m.PQRS is the region inside the garden.so,PQ = (30 -1-1 ) = 28 malsoPS = ( 30 – 1 – 1 ) = 28 m (i) Area of the path = Area of ABCD – Area of PQRS = [( 30 x 30) – (28 x 28)]= 900 – 784

answer Let ABCD, the square garden of side= 30 m.PQRS is the region inside the garden.so,PQ = (30 -1-1 ) = 28 malsoPS = ( 30 – 1 – 1 ) = 28 m (i) Area of the path = Area of ABCD – Area of PQRS = [( 30 x 30) – (28 x 28)]= 900 – 784 = 116 sq.m

answer Let ABCD, the square garden of side= 30 m.PQRS is the region inside the garden.so,PQ = (30 -1-1 ) = 28 malsoPS = ( 30 – 1 – 1 ) = 28 m (i) Area of the path = Area of ABCD – Area of PQRS = [( 30 x 30) – (28 x 28)]= 900 – 784 = 116 sq.m (ii) Area of the remaining portion in which the grass is planted = Area of square PQRS

answer Let ABCD, the square garden of side= 30 m.PQRS is the region inside the garden.so,PQ = (30 -1-1 ) = 28 malsoPS = ( 30 – 1 – 1 ) = 28 m (i) Area of the path = Area of ABCD – Area of PQRS = [( 30 x 30) – (28 x 28)]= 900 – 784 = 116 sq.m (ii) Area of the remaining portion in which the grass is planted = Area of square PQRS = 28 x 28

answer Let ABCD, the square garden of side= 30 m.PQRS is the region inside the garden.so,PQ = (30 -1-1 ) = 28 malsoPS = ( 30 – 1 – 1 ) = 28 m (i) Area of the path = Area of ABCD – Area of PQRS = [( 30 x 30) – (28 x 28)]= 900 – 784 = 116 sq.m (ii) Area of the remaining portion in which the grass is planted = Area of square PQRS = 28 x 28 = 784 sq.m

answer Let ABCD, the square garden of side= 30 m.PQRS is the region inside the garden.so,PQ = (30 -1-1 ) = 28 malsoPS = ( 30 – 1 – 1 ) = 28 m (i) Area of the path = Area of ABCD – Area of PQRS = [( 30 x 30) – (28 x 28)]= 900 – 784 = 116 sq.m (ii) Area of the remaining portion in which the grass is planted = Area of square PQRS = 28 x 28 = 784 sq.m cost of planting the grass in the region PQRS = area x cost = 764 x 40

answer Let ABCD, the square garden of side= 30 m.PQRS is the region inside the garden.so,PQ = (30 -1-1 ) = 28 malsoPS = ( 30 – 1 – 1 ) = 28 m (i) Area of the path = Area of ABCD – Area of PQRS = [( 30 x 30) – (28 x 28)]= 900 – 784 = 116 sq.m (ii) Area of the remaining portion in which the grass is planted = Area of square PQRS = 28 x 28 = 784 sq.m cost of planting the grass in the region PQRS = area x cost = 764 x 40 =31,360