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1
ATQ,
x=(-1)
so,
ax³-x²+x+4=0
a(-1)³-(-1)²+(-1)+4=0
a(-1)-(1)-1+4=0
-a-1-1+4=0
-a+2=0
-a=-2
a=2
x=(-1)
so,
ax³-x²+x+4=0
a(-1)³-(-1)²+(-1)+4=0
a(-1)-(1)-1+4=0
-a-1-1+4=0
-a+2=0
-a=-2
a=2
Answered by
0
p(x)= -1
p(x)= ax³-x²+x+ 4 = 0
= a(-1)³ - (-1)²+ (-1)+4=0
= -a -1 -1 +4 =0
=-a -2+4= 0
=-a -2= -4
=-a =-4 +2
= -a = -2
therefore , a = 2
p(x)= ax³-x²+x+ 4 = 0
= a(-1)³ - (-1)²+ (-1)+4=0
= -a -1 -1 +4 =0
=-a -2+4= 0
=-a -2= -4
=-a =-4 +2
= -a = -2
therefore , a = 2
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