Question

Answer question no. 24

Answer 1

I think this question ans is B

Answer 2

angle between the chords = 65°

Hence, angle subtended by an arc BC =65°

So, angle subtended by arc BC at the centre = 2× 65°

angle COB = 130°.

Also, we know that, radius is perpendicular to the tangent through the point of contact.

Therefore, angle OBP = angle OCP = 90°

NOW, In quadrilateral OBPC:-

angle OBP + angle OCP + angle BPC + angle COB = 360°

90° + 90° + 130° + angle COB = 360°

angle COB = 360°- 310°

= 50°

HENCE, angle between two tangents = 59°

HOPE IT HELPS YOU.