Question

answer question no. 9​

Answer 1

1. Since (X+2) is the factor of ax3+bx2+x-6.

So,

p(X)÷ (X+2)=0

Then, find the zero of (X+2)

= X=2

Put the value of X in p(X).

And you will get

a= 2-b/2-----------(1)

Now,

in the case of (x-2)

find the value of X by the Zeroes of polynomial.

Put the value of X in p(X).

Then, the equation is in the form,

ax3+bx2+x-6= 4

You will get

b= 2.

Put the value of b in equation (1),

you will get the value of a.

Answer 2

Answer:

answer2,4......

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