Math, asked by Anonymous, 1 year ago

Answer question please fast and explain it step by step

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Answered by Anonymous
3

Answer:

1 ) diameter of the sphere ( d ) = 6cm

radius of the sphere ( r ) = d/2 = 6/2 = 3cm

2 ) diameter of the cylindrical vessel ( D ) = 12 cm

radius of the cylindrical vessel ( R ) = 12/2 = 6 cm

level of water raised = h cm

according to the problem given ,

volume of the water raised in the vessel = volume of the sphere

πR²h = 4/3 × πr³

h = ( 4 × r³ ) / ( 3 × R² )

h = ( 4 × 3 × 3 × 3 ) / ( 3 × 6 × 6 )

h = 1 cm

Therefore ,

level of water raised in the vessel = h = 1 cm

I hope this helps you.

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Gautambmw2Helping Hand

1 ) diameter of the sphere ( d ) = 6cm

radius of the sphere ( r ) = d/2 = 6/2 = 3cm

2 ) diameter of the cylindrical vessel ( D ) = 12 cm

radius of the cylindrical vessel ( R ) = 12/2 = 6 cm

level of water raised = h cm

according to the problem given ,

volume of the water raised in the vessel = volume of the sphere

πR²h = 4/3 × πr³

h = ( 4 × r³ ) / ( 3 × R² )

h = ( 4 × 3 × 3 × 3 ) / ( 3 × 6 × 6 )

h = 1 cm

Therefore ,

level of water raised in the vessel = h = 1 cm

Answered by Anonymous
2

Answer:

here is your answer in the attachment hope this is helpful

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