Question

answer question with photos​

Answer 1

We are given an equation $\dfrac{a}{b}+\dfrac{b}{a}=1$.

Now let's simply take the LCM in the L.H.S.,

$\dfrac{a^2+b^2}{ab}=1$

Now, let's multiply ab on both the sides, i.e., the L.H.S. and the R.H.S.

$\dfrac{a^2+b^2}{\cancel{ab}}\times \cancel{ab}=1\times ab$

Simplify.

$a^2+b^2=ab$

So, now let's subtract ab from both sides.

$a^2+b^2 -ab=ab-ab$

Simplify. :)

$a^2+b^2-ab=0$

Now, We know an Algebraic identity, $a^3+b^3=(a+b) (a^2 -ab+b^2)$

So, keeping this identity in our mind, let's solve our question;

Now, let's take the question that we have to find;

$a^3+b^3=?$

$\implies a^3+b^3=(a+b)(a^2 -ab+b^2)$

Now, we already knew the value of $a^2+b^2-ab$ or $a^2-ab+b^2$ which is equal to 0.

So let's plug in the value and chug!!

$a^3+b^3=(a+b)(0)$

Simplify; :)

$\bold{a^3+b^3=0}$

Answer 2

Answer:

A power 3 + B power 3 =0

I hope it will help you yaar