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plz write the full question it's incomplete
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- Option 1 : 100 m
El
Given:
- Initial velocity = 0 m/s
- Final velocity = 144 km/hr = 40 m/s
- Time taken = 5s
To Find:
- Distance covered
Concept:
- First we have to find the acceleration of the car. Substituting the data in the second or third equation of motion we get the distance covered by the car.
Solution:
- Initially we have to find the acceleration of the car
- By the first equation of motion,
- v = u + at
- where v = final velocity
- u = initial velocity
- a = acceleration
- t = time taken
Substitute the data
- 40 = 0 + a × 5
- 5a = 40
- a = 40/5
a = 8 m/s²
- Hence acceleration of the car is 8 m/s²
- Now we have to find the distance covered by the car
- By the third equation of motion,
v² - u² = 2as
- where v = final velocity
- u = initial velocity
- a = acceleration
- s = distance covered
Substituting the data,
- 40² - 0² = 2 × 8 × s
- 16s = 1600
- s = 1600/16
s = 100 m
Hence the distance covered by the car is 100 m
Therefore option 1 is correct.
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