Question

answer questions in the attachment​

Answer 1

Heya mate!!

In TriangleABD =

$\frac{1}{2} \times 6.4 \times 3 = 9.6 {m}^{2}$

Area of ∆BON = 9.6+9.6 = 19.2m^2

∆BON is congruent with ∆AMP

Area of ∆AMP=19.2m^2

Area of rectangle MNOP=14×6=84m^2

Area of shaded region = 84-38.4

45.6m^2

Hope it helps u dear✌️✌️