Question

answer questions please​

Answer 1

Answer:

B)

PTR/100 = 2a⁴

C)

xyz = 75a⁴

Answer 2

Question B)

Given :

• P = 4a²
• R = 5a
• T = 10a

To find :

$\sf \: Value \: of\: \dfrac{PTR}{100}$

Solution :

Put value P, R, T in above equation

$\sf \implies \: \dfrac{(4 {a}^{2}) \times \: 10a \times 5a }{100}$

$\sf \implies \: \dfrac{200 \times {a}^{(2 + 1 + 1)} }{100}$

$\sf \implies \: 2{a}^{4}$

Answer B : 2a⁴

________________________________

Question C)

Given :

• x = a²
• y = 5a
• z = 15a

To find :

Value of xyz

Solution :

Put value of x,y,z in xyz

$\sf \implies \: (a^{2}) \times (5a) \times (15a)$

$\sf \implies \: 75 \times (a^{(2 + 1 + 1)})$

$\sf \implies \: 75a^{4 }$

Answer C : 75a⁴

________________________________