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as per 10 th board patern
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draw a line through D parallel to BF and name it as DH
since BF is parallel to DH
BD\DC = FH\HC
1=FH\HC since BD = Dc
FH=HC
BF is parallel to DH
therefore GF is parallel to DH
AG/GD = AF/FH
1=AF/FH since AG= GD
AF = FH
therefore AF=FH=HC
AC=AF+FH+HC
AC=3AF
AF= 1/3 AC
hope it helps..
pls mark it as brainliest answer
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