Question

Answer quickly.....................

Answer 1

Explanation:

This is a limiting reagent (LR) problem and you know that because an amount is given for each reactant (in this cse 10 g each).

2MnI2(s) + 13F2(g)--> 2MnF3(s) + 4IF5(l)

mols MnI2 = grams/molar mass = ?

mols F2 = grams/molar mass = ?

Using the coefficients in the balanced equation, convert mols MnI2 to mols MnF3.

Do the same to convert mols F2 to mols MnF3.

It is likely that the two values will not agree which means one is not right. The correct value in LR problems is ALWAYS the smaller value and the reagent responsible for producing that amount is the LR.

Using the smaller amount convert mols to grams. grams = mols x molar mass.

That is the 100% (theoretical yield). To find the yield ad 56%. then

theoretical yield x 0.56 = ?

mols MnI2=0.03246

mols F2=0.26315

3.875g MnF3