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Three blocks of masses 2kg 3 kg and 4 kg are placed one over the other as shown in the figure
calculate the force exerted by the blocks of mass 2 kg and 4 kg on the 3 ky block (g = 10 m/sa).
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Answered by
0
Answer:
20Nand70N
Explanation:
F=ma (a=g=10m/s2)
=2×10
=20N
F=ma
=(3+4)×10
=70N
Answered by
0
Answer:
F=45-9=36N
F=M,A
F=36/4=4M/S²
N-9=4×9
N=16+9
N=25N
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