Question

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Answer 1

Hello bro......

Assume speed of bus leaving from Point A as ‘a' and bus leaving from Point B as ‘b' now we have 2 equations here

First assume that when they are moving in the same direction they meet in time t and they are moving away from Point A. Assume after time t bus from B has travelled x km. So bus from Point A has travelled (x+60) km.

Equation 1 is

b*t+60= a*t

Here t is 6hrs therefore

6b+60= 6a

a-b=10……..(i)

When they are travelling in opposite direction they are moving towards each other. Which means when the buses meet if b has travelled x km then bus from point A has travelled (60-x) km

Equation 2 is

60- (b*t)=a*t

Here t is 2 hrs therefore

60 - 2b= 2a

a+b=30…….(ii)

Solving (i) and (ii) we get

a=20

b=10

If we assume that when travelling in same direction if they both are travelling away from Point B then b=20 and a=10

But the faster bus will be moving at 20km/hr

Hope helps.....