Math, asked by yuvan200537, 4 months ago

Answer required with steps​

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Answered by senboni123456
2

Step-by-step explanation:

Let the required points be  (h,k)

It is given that, the point  (h,k) is equidistant from points  (2,3)  and (-2,5)

So,

 \sqrt{(h - 2) ^{2}  +  {(k - 3)}^{2} }  =  \sqrt{ {(h + 2)}^{2} +  {(k - 5)}^{2}  }  \\

Squaring both sides,

  \implies(h - 2) ^{2}  +  {(k - 3)}^{2}  =  {(h + 2)}^{2} +  {(k - 5)}^{2}   \\

  \implies  {(k - 3)}^{2} - {(k - 5)}^{2}    =  {(h + 2)}^{2}  -  {(h - 2)}^{2}  \\

  \implies  (k^{2}   - 6k + 9)- ({k}^{2} - 10k + 25)    = 8h \\

  \implies  k^{2}   - 6k + 9- {k}^{2}  + 10k  -  25   = 8h \\

  \implies     4k + 16   = 8h \\

  \implies     k + 4   = 2h \\

  \implies      2h - k - 4 = 0 \\

Hence the required locus of the point  2x - y -4 =0

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