Answer:
Resistive force of the bullet is -128N
Explanation:
Given,
A bullet of mass 20g moving with a velocity of 80m/s hits a wooden block and stops after a distance of 50cm is covered.
Find the average resistive force exerted by the block.
Average resistive force is given by,
\implies \: {\rm F} = ma⟹F=ma
Where,
\boldsymbol mm denotes the mass of the bullet.
\boldsymbol aa is the acceleration.
Lets calculate the acceleration.
We have,
uu (intial velocity) = 80m/s
vv (final velocity) = 0m/s [Since it comes to rest]
ss (distance) = 50cm or, 0.5m [On conversion]
By using the 3rd equation of motion,
\implies \: 2as = {v}^{2} - {u}^{2}⟹2as=v2−u2
Substitute the values,
\implies \: 2(a)(0.5) = {0}^{2} - {80}^{2}⟹2(a)(0.5)=02−802
\implies \: 1a = - 6400⟹1a=−6400
\implies \: a = - 6400⟹a=−6400
Now calculate the resistive force :-
Converting mass into kg
= 20g ÷ 1000 [Since 1kg = 1000g]
= 0.020 kg
\therefore \: \rm F = 0.020 \times ( - 6400)∴F=0.020×(−6400)
\implies \: \rm F = - 128⟹F=−128
Hence, the resistive force exerted by the wooden block is -128N
[Note: -ve sign denotes the opposite force ]
Answers
Answered by
11
Answer:
Rimi
Oxygen is correct answer
I think so,
please report my answer
Answered by
5
Answer:
Oxygen is the correct one .
Hoped its helpful
Similar questions