Math, asked by Dheeraj431, 8 months ago

answer step by step​

Attachments:

Answers

Answered by jyosthna456
1

Answer:

hope this answer helpful

if it is helpful mark as brainliest

Attachments:
Answered by getsparkling
0

Answer:

x/ y + y/x = -1

(x^2+y^2)/xy= -1

x^2 + y^2= - xy -- (1)

x^3-y^3= ( x-y)(x^2+y^2+xy) -- (2)

Substitute equation (1) in equation (2)

x^3-y^3= (x-y)( -xy + xy)

x^3-y^3= (x-y)(0)

Therefore,

x^3-y^3= 0

Hope it helps!

Similar questions