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sorry mate I can't solve it right now I will solve later
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25^x-1 = 5^2x-1 - 100
⇒ 5^2x-2 = 5^(2x-1) - 100
⇒ 5^2x-2 - 5^2x-1 = -100
⇒ 5^2x [ 5^-2 - 5^-1] = - 100
⇒ 5^2x [ 1 - 1 ] = - 100
25 5
⇒ 5^2x [ 1 - 5 ] = - 100
25
⇒ 5^2x [ -4 ] = - 100
25
⇒ 5^2x [-4] = -100 * 25
⇒ 5^2x = 100 * 25 [ - * - = +]
4
⇒ 5^2x = 625
⇒ 5^2x = 5^4
so, ⇒ 2x = 4
⇒ x=2
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