Question

answer step by step​

Answer 1

Hey Here's Your Answer...

Finding the LCM of 3,1and 6 which is 6.

then,

$\frac{(6x + 1) \times 2}{3 \times 2 } + \frac{1 \times 6}{1 \times 6} = \frac{x - 3}{6}$

then,

$\frac{12x + 2}{6} + \frac{6}{6} = \frac{x - 3}{6}$

then,

$\frac{12x + 2 + 6}{6} = \frac{x - 3}{6}$

then,

$\frac{12x + 8}{6} = \frac{x - 3}{6}$

then,

$\frac{12x}{6} + \frac{8}{6} = \frac{x}{6} - \frac{3}{6}$

then,

(multiplying both side by 6)

${12x}+ {8} = {x} - {3}$

then,

$12x - x + 8 = - 3$

then,

$11x = - 3 - 8$

then,

$11x = - 11x$

then,

$x = \frac{ - 11}{11}$

then,

$x = - 1$

We reach to am end. Hence we completed our answer....

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