answer step by step please
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sorry I had no points so I type this
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Step-by-step explanation:
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∵AE║BD
∴AB acts as a transversal
∴∠EAB = ∠ABD [Alternate angles]------>(1)
now ∵AF and BC are angle bisectors;
∴ ∠EAB = ∠EAF + ∠FAB----->(2)
and ∠ABD =∠ABC + ∠CBD------>(3)
∴from (1), (2) and (3) we get
∠EAF + ∠FAB = ∠ABC + ∠CBD
2∠FAB = 2∠ABC
or ∠FAB = ∠ABC
now ∠FAB and ∠ABC act as alternate angles for lines AF and BC with transversal AB
Hence using converse of alternate angle theorem; we get
AF║BC
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