Question

Answer the 10 question

Answer 1

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Answer 2

(1) Given ax + by - 2a + 3b = 0

               ax + by = 2a - 3b  ---------------------------- (1)


(2) Given bx - ay = 3a + 2b   --------------------------- (2)


On solving (1) * a & (2) * b, we get

a^2x + aby = 2a^2 - 3ab

b^2x - aby = 2b^2 + 3ab

---------------------------------

a^2x + b^2x = 2a^2 - 3ab + 2b^2 + 3ab

x(a^2 + b^2) = 2(a^2 + b^2)

x = 2(a^2 + b^2)/(a^2 + b^2)

   = 2.


Substitute x = 2 in (2), we get

bx - ay = 3a + 2b

b(2) - ay = 3a + 2b

2b - ay = 3a + 2b

-ay = 3a + 2b - 2b

-ay = 3a

y = - 3a/a

y = 3.


Therefore x = 2 and y = -3.


Hope this helps!