answer the 16th question
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Heya mate here's your answer:-
The given condition forms x greater than y greater than z.
Resistance of AB is x,across CD is y and across EF is z as given in the figure in the given rectangular cross section (a×2a×4a).
- Resistance= pL/A
where p=resistivity
- L=length of the conductor
- A=area of cross section
For resistance between A and B
- L=4a
- A=2a*4a
- x=p a/(2a×4a)=p/8a=(1/8)(p/a)
For resistance between E and F
- L=4a
- A=a*4a
- z=p a/(a×4a)=p/2a=(1/2)(p/a)
Hence, option 2.) x greater than y greater than z
HOPE THIS HELPS...
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