Question

Answer the 17th question

Answer 1

Please see the attachment

Answer 2

Answer: Proved

Step-by-step explanation:

Given :  In Δ  ABC  , right angled at where AB is the perpendicular , BC is the base and AC is the Hypotenuse.

To prove : 4 (LC)² = (AB)² + 4 (BC)²

Proof :  L is the mid point of AB

So, AB = BL + AL

In Δ LBC

By using pythagorus theorem

( LC)² = (LB)² +( BC)²

(LC)² = (AB/ 2)² +( BC)²

(LC )²= AB ²/4 + (BC)²

(LC ) ² = AB² + 4 BC ² / 4

4 ( LC )² = AB² + 4 (BC) ²

Hence proved