answer the 2 nd one pls
with explanation
I will mark the 1 st ans as brainliest
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2x^3+x^2-5x+2
(1/2,1,-2)
2(1/2)^3+(1/2)^2-5(1/2)+2=0
2(1)^3+(1)^2-5(1)+2=0
2(-2)^3+(-2)^2-5(-2)+2=0
sum of zeroes =1/2+1-2=-1/2 = -(coefficient of x^2 /coefficient of x^3)
product of zeroes=1/2*1*(-2)=(-1) = -(constant/coefficient of x^3)
(1/2,1,-2)
2(1/2)^3+(1/2)^2-5(1/2)+2=0
2(1)^3+(1)^2-5(1)+2=0
2(-2)^3+(-2)^2-5(-2)+2=0
sum of zeroes =1/2+1-2=-1/2 = -(coefficient of x^2 /coefficient of x^3)
product of zeroes=1/2*1*(-2)=(-1) = -(constant/coefficient of x^3)
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